Alkyl Halide Reactions
The functional group of alkyl halides is a carbon-halogen bond, the common halogens being fluorine, chlorine, bromine and iodine. With the exception of iodine, these halogens have electronegativities significantly greater than carbon. Consequently, this functional group is polarized so that the carbon is electrophilic and the halogen is nucleophilic, as shown in the drawing on the right. Two characteristics other than electronegativity also have an important influence on the chemical behavior of these compounds. The first of these is covalent bond strength. The strongest of the carbon-halogen covalent bonds is that to fluorine. Remarkably, this is the strongest common single bond to carbon, being roughly 30 kcal/mole stronger than a carbon-carbon bond and about 15 kcal/mole stronger than a carbon-hydrogen bond. Because of this, alkyl fluorides and fluorocarbons in general are chemically and thermodynamically quite stable, and do not share any of the reactivity patterns shown by the other alkyl halides. The carbon-chlorine covalent bond is slightly weaker than a carbon-carbon bond, and the bonds to the other halogens are weaker still, the bond to iodine being about 33% weaker. The second factor to be considered is the relative stability of the corresponding halide anions, which is likely the form in which these electronegative atoms will be replaced. This stability may be estimated from the relative acidities of the H-X acids, assuming that the strongest acid releases the most stable conjugate base (halide anion). With the exception of HF (pKa = 3.2), all the hydrohalic acids are very strong, small differences being in the direction HCl < HBr < HI.
Substitution and EliminationThe characteristics noted above lead us to anticipate certain types of reactions that are likely to occur with alkyl halides. In describing these, it is useful to designate the halogen-bearing carbon as alpha and the carbon atom(s) adjacent to it as beta, as noted in the first four equations shown below. Replacement or substitution of the halogen on the α-carbon (colored maroon) by a nucleophilic reagent is a commonly observed reaction, as shown in equations 1, 2, 5, 6 & 7 below. Also, since the electrophilic character introduced by the halogen extends to the β-carbons, and since nucleophiles are also bases, the possibility of base induced H-X elimination must also be considered, as illustrated by equation 3. Finally, there are some combinations of alkyl halides and nucleophiles that fail to show any reaction over a 24 hour period, such as the example in equation 4. For consistency, alkyl bromides have been used in these examples. Similar reactions occur when alkyl chlorides or iodides are used, but the speed of the reactions and the exact distribution of products will change.
In order to understand why some combinations of alkyl halides and nucleophiles give a substitution reaction, whereas other combinations give elimination, and still others give no observable reaction, we must investigate systematically the way in which changes in reaction variables perturb the course of the reaction. The following general equation summarizes the factors that will be important in such an investigation.
One conclusion, relating the structure of the R-group to possible
products, should be immediately obvious. If R- has no beta-hydrogens
an elimination reaction is not possible, unless a structural
rearrangement occurs first. The first four halides shown on the left
below do not give elimination reactions on treatment with base, because
they have no β-hydrogens. The two halides on the right do not normally
undergo such reactions because the potential elimination products have
highly strained double or triple bonds.
Using the general reaction shown above as our reference, we can identify the following variables and observables.
When several reaction variables may be changed, it is important to isolate the effects of each during the course of study. In other words: only one variable should be changed at a time, the others being held as constant as possible. For example, we can examine the effect of changing the halogen substituent from Cl to Br to I, using ethyl as a common Rgroup, cyanide anion as a common nucleophile, and ethanol as a common solvent. We would find a common substitution product, C2H5CN, in all cases, but the speed or rate of the reaction would increase in the order: Cl < Br < I. This reactivity order reflects both the strength of the CX bond, and the stability of X() as a leaving group, and leads to the general conclusion that alkyl iodides are the most reactive members of this functional class. 1. NucleophilicityRecall the definitions of electrophile and nucleophile:
Electrophile:
An electron deficient atom, ion or molecule that has an affinity for
an electron pair, and will bond to a base or nucleophile. If we use a common alkyl halide, such as methyl bromide, and a common solvent, ethanol, we can examine the rate at which various nucleophiles substitute the methyl carbon. Nucleophilicity is thereby related to the relative rate of substitution reactions at the halogen-bearing carbon atom of the reference alkyl halide. The most reactive nucleophiles are said to be more nucleophilic than less reactive members of the group. The nucleophilicities of some common Nu:() reactants vary as shown in the following chart.
Nucleophilicity:
CH3CO2()
< Cl()
< Br()
< N3()
< CH3O()
< CN()
< I()
< SCN()
< I()
< CH3S()
The reactivity range encompassed by these reagents is over 5,000 fold, thiolate being the most reactive. Note that by using methyl bromide as the reference substrate, the complication of competing elimination reactions is avoided. The nucleophiles used in this study were all anions, but this is not a necessary requirement for these substitution reactions. Indeed reactions 6 & 7, presented at the beginning of this section, are examples of neutral nucleophiles participating in substitution reactions. The cumulative results of studies of this kind has led to useful empirical rules pertaining to nucleophilicity:
(i)
For a given element, negatively charged species are more nucleophilic
(and basic) than are equivalent neutral species.
2. Solvent EffectsSolvation of nucleophilic anions markedly influences their reactivity. The nucleophilicities cited above were obtained from reactions in methanol solution. Polar, protic solvents such as water and alcohols solvate anions by hydrogen bonding interactions, as shown in the diagram on the right. These solvated species are more stable and less reactive than the unsolvated "naked" anions. Polar, aprotic solvents such as DMSO (dimethyl sulfoxide), DMF (dimethylformamide) and acetonitrile do not solvate anions nearly as well as methanol, but provide good solvation of the accompanying cations. Consequently, most of the nucleophiles discussed here react more rapidly in solutions prepared from these solvents. These solvent effects are more pronounced for small basic anions than for large weakly basic anions. Thus, for reaction in DMSO solution we observe the following reactivity order:
Nucleophilicity:
I()
< SCN()
< Br()
< Cl()
≈ N3()
< CH3CO2
()
< CN()
≈ CH3S()
< CH3O() Note that this order is roughly the order of increasing basicity.
3. The Alkyl Moiety
Some of the most important information concerning nucleophilic
substitution and elimination reactions of alkyl halides has come from
studies in which the structure of the alkyl group has been varied. If we
examine a series of alkyl bromide substitution reactions with the strong
nucleophile thiocyanide (SCN) in ethanol solvent, we find large
decreases in the rates of reaction as alkyl substitution of the
alpha-carbon increases. Methyl bromide reacts 20 to 30 times faster than
simple 1Ί-alkyl bromides, which in turn react about 20 times faster than
simple 2Ί-alkyl bromides, and 3Ί-alkyl bromides are essentially
unreactive or undergo elimination reactions. Furthermore, β-alkyl
substitution also decreases the rate of substitution, as witnessed by
the failure of neopentyl bromide, (CH3)3CCH2-Br
(a 1Ί-bromide), to react. (S)-CH3CHICH2CH3 + NaN3 > (R)-CH3CHN3CH2CH3 + NaI
We can now piece together a plausible picture of how nucleophilic
substitution reactions of 1Ί and 2Ί-alkyl halides take place. The
nucleophile must approach the electrophilic alpha-carbon atom from the
side opposite the halogen. As a covalent bond begins to form between the
nucleophile and the carbon, the carbon halogen bond weakens and
stretches, the halogen atom eventually leaving as an anion. The diagram
on the right shows this process for an anionic nucleophile. We call this
description the SN2
mechanism, where S stands for Substitution, N
stands for Nucleophilic and 2 stands for bimolecular
(defined below). In the SN2
transition state the alpha-carbon is hybridized sp2 with
the partial bonds to the nucleophile and the halogen having largely
p-character. Both the nucleophile and the halogen bear a partial
negative charge, the full charge being transferred to the halogen in the
products. The consequence of rear-side bonding by the nucleophile is an
inversion of configuration about the alpha-carbon. Neutral nucleophiles
react by a similar mechanism, but the charge distribution in the
transition state is very different. The two models displayed below start as methyl bromide, on the left, and ethyl bromide, on the right. These may be replaced by isopropyl, tert-butyl, neopentyl, and benzyl bromide models by pressing the appropriate buttons. (note that when first activated, this display may require clicking twice on the selected button.) In each picture the nucleophile is designated by a large deep violet sphere, located 3.75 Angstroms from the alpha-carbon atom (colored a dark gray), and located exactly opposite to the bromine (colored red-brown). This represents a point on the trajectory the nucleophile must follow if it is to bond to the back-side of the carbon atom, displacing bromide anion from the front face. With the exception of methyl and benzyl, the other alkyl groups present a steric hindrance to the back-side approach of the nucleophile, which increases with substitution alpha and beta to the bromine. The hydrogen (and carbon) atoms that hinder the nucleophile's approach are colored a light red. The magnitude of this steric hindrance may be seen by moving the models about in the usual way, and is clearly greatest for tert-butyl and neopentyl, the two compounds that fail to give substitution reactions.
4. MolecularityIf a chemical reaction proceeds by more than one step or stage, its overall velocity or rate is limited by the slowest step, the rate-determining step. This "bottleneck concept" has analogies in everyday life. For example, if a crowd is leaving a theater through a single exit door, the time it takes to empty the building is a function of the number of people who can move through the door per second. Once a group gathers at the door, the speed at which other people leave their seats and move along the aisles has no influence on the overall exit rate. When we describe the mechanism of a chemical reaction, it is important to identify the rate-determining step and to determine its "molecularity". The molecularity of a reaction is defined as the number of molecules or ions that participate in the rate determinining step. A mechanism in which two reacting species combine in the transition state of the rate-determining step is called bimolecular. If a single species makes up the transition state, the reaction would be called unimolecular. The relatively improbable case of three independent species coming together in the transition state would be called termolecular.
5. KineticsOne way of investigating the molecularity of a given reaction is to measure changes in the rate at which products are formed or reactants are lost, as reactant concentrations are varied in a systematic fashion. This sort of study is called kinetics, and the goal is to write an equation that correlates the observed results. Such an equation is termed a kinetic expression, and for a reaction of the type: A + B > C + D it takes the form: Reaction Rate = k[A] n[B] m, where the rate constant k is a proportionality constant that reflects the nature of the reaction, [A] is the concentration of reactant A, [B] is the concentration of reactant B, and n & m are exponential numbers used to fit the rate equation to the experimental data. Chemists refer to the sum n + m as the kinetic order of a reaction. In a simple bimolecular reaction n & m would both be 1, and the reaction would be termed second order, supporting a mechanism in which a molecule of reactant A and one of B are incorporated in the transition state of the rate-determining step. A bimolecular reaction in which two molecules of reactant A (and no B) are present in the transition state would be expected to give a kinetic equation in which n=2 and m=0 (also second order). The kinetic expressions found for the reactions shown at the beginning of this section are written in blue in the following equations. Each different reaction has its own distinct rate constant, k#. All the reactions save 7 display second order kinetics, reaction 7 is first order.
It should be recognized and remembered that the molecularity of a
reaction is a theoretical term referring to a specific mechanism. On the
other hand, the kinetic order of a reaction is an experimentally derived
number. In ideal situations these two should be the same, and in most of
the above reactions this is so. Reaction
7
above is clearly different from the other cases reported here. It not
only shows first order kinetics (only the alkyl halide concentration
influences the rate), but the chiral 3Ί-alkyl bromide reactant undergoes
substitution by the modest nucleophile water with extensive racemization.
Note that the acetonitrile cosolvent does not function as a nucleophile.
It serves only to provide a homogeneous solution, since the alkyl halide
is relatively insoluble in pure water. Two discrete mechanisms for nucleophilic substitution reactions will be described in the next section.
Reactions of Alkyl Halides with Reducing MetalsThe alkali metals (Li, Na, K etc.) and the alkaline earth metals (Mg and Ca, together with Zn) are good reducing agents, the former being stronger than the latter. Sodium, for example, reduces elemental chlorine to chloride anion (sodium is oxidized to its cation), as do the other metals under varying conditions. In a similar fashion these same metals reduce the carbon-halogen bonds of alkyl halides. The halogen is converted to halide anion, and the carbon bonds to the metal (the carbon has carbanionic character). Halide reactivity increases in the order: Cl < Br < I. The following equations illustrate these reactions for the commonly used metals lithium and magnesium (R may be hydrogen or alkyl groups in any combination). The alkyl magnesium halides described in the second reaction are called Grignard Reagents after the French chemist who discovered them. The other metals mentioned above react in a similar manner, but the two shown here are the most widely used. Although the formulas drawn here for the alkyl lithium and Grignard reagents reflect the stoichiometry of the reactions and are widely used in the chemical literature, they do not accurately depict the structural nature of these remarkable substances. Mixtures of polymeric and other associated and complexed species are in equilibrium under the conditions normally used for their preparation.
The metals referred to here are insoluble in most organic solvents,
hence these reactions are clearly heterogeneous, i.e. take place on the
metal surface. The conditions necessary to achieve a successful reaction
are critical. These reactions are obviously substitution reactions, but they cannot be classified as nucleophilic substitutions, as were the earlier reactions of alkyl halides. Because the functional carbon atom has been reduced, the polarity of the resulting functional group is inverted (an originally electrophilic carbon becomes nucleophilic). This change, shown below, makes alkyl lithium and Grignard reagents unique and useful reactants in synthesis.
Reactions of organolithium and Grignard reagents reflect the nucleophilic (and basic) character of the functional carbon in these compounds. Many examples of such reactions will be encountered in future discussions, and five simple examples are shown below. The first and third equations demonstrate the strongly basic nature of these compounds, which bond rapidly to the weakly acidic protons of water and methyl alcohol (colored blue). The nucleophilic carbon of these reagents also bonds readily with electrophiles such as iodine (second equation) and carbon dioxide (fifth equation). The polarity of the carbon-oxygen double bonds of CO2 makes the carbon atom electrophilic, shown by the formula in the shaded box, so the nucleophilic carbon of the Grignard reagent bonds to this site. As noted above, solutions of these reagents must also be protected from oxygen, since peroxides are formed (equation 4).
Another important reaction exhibited by these organometallic reagents is metal exchange. In the first example below, methyl lithium reacts with cuprous iodide to give a lithium dimethylcopper reagent, which is referred to as a Gilman reagent. Other alkyl lithiums give similar Gilman reagents. A useful application of these reagents is their ability to couple with alkyl, vinyl and aryl iodides, as shown in the second equation. Later we shall find that Gilman reagents also display useful carbon-carbon bond forming reactions with conjugated enones and with acyl chlorides.
The formation of organometallic reagents from alkyl halides is more tolerant of structural variation than were the nucleophilic substitutions described earlier. Changes in carbon hybridization have little effect on the reaction, and 1Ί, 2Ί and 3Ί-alkyl halides all react in the same manner. One restriction, of course, is the necessary absence of incompatible functional groups elsewhere in the reactant molecule. For example, 5-bromo-1-pentanol fails to give a Grignard reagent (or a lithium reagent) because the hydroxyl group protonates this reactive function as soon as it is formed. BrCH2CH2CH2CH2CH2OH + Mg > [ BrMgCH2CH2CH2CH2CH2OH ] > HCH2CH2CH2CH2CH2OMgBr
Reactions of DihalidesIf two halogen atoms are present in a given compound, reactions with reducing metals may take different paths depending on how close the carbon-halogen bonds are to each other. If they are separated by four or more carbons, as in the first example below, a bis-organometallic compound may be formed. However, if the halogens are bonded to adjacent (vicinal) carbons, an elimination takes place with formation of a double bond. Since vicinal-dihalides are usually made by adding a halogen to a double bond, this reaction is mainly useful for relating structures to each other. The last example, in which two halogens are bonded to the same carbon, referred to as geminal (twinned), gives an unusual reagent which may either react as a carbon nucleophile or, by elimination, as a carbene. Such reagents are often termed carbenoid.
The solution structure of the Simmons-Smith reagent is less well understood than that of the Grignard reagent, but the formula given here is as useful as any that have been proposed. Other alpha-halogenated organometallic reagents, such as ClCH2Li, BrCH2Li, Cl2CHLi and Cl3CLi, have been prepared, but they are substantially less stable and must be maintained at very low temperature (ca. -100 Ί C) to avoid loss of LiX. The stability and usefulness of the Simmons-Smith reagent may be attributed in part to the higher covalency of the carbon-zinc bond together with solvation and internal coordination of the zinc. Hydrolysis (reaction with water) gives methyl iodide, confirming the basicity of the carbon; and reaction with alkenes gives cyclopropane derivatives, demonstrating the carbene-like nature of the reagent. The latter transformation is illustrated by the equation on the right. Elimination reactions of the stereoisomeric 1,2-dibromo-1,2-diphenylethanes provide a nice summary of the principles discussed above. The following illustration shows first the meso-diastereomer and below it one enantiomer of the racemic-diastereomer. In each case two conformers are drawn within parentheses, and the anti-relationship of selected vicinal groups in each is colored green. The reaction proceeding to the left is a dehydrohalogenation induced by treatment with KOH in alcohol. Since this is a stereospecific elimination, each diastereomer gives a different stereoisomeric product. The reaction to the right is a dehalogenation (the reverse of halogen addition to an alkene), caused by treatment with iodide anion. Zinc dust effects the same reaction, but with a lower degree of stereospecificity. The mechanism of the iodide anion reaction is shown by red arrows in the top example. A similar mechanism explains the comparable elimination of the racemic isomer. In both reactions an anti-transition state is observed.
The two stereoisomers of 1-bromo-1,2-diphenylethene (shown on the left of the diagram) undergo a second dehydrobromination reaction on more vigorous treatment with base, as shown in the following equation. This elimination generates the same alkyne (carbon-carbon triple bond) from each of the bromo-alkenes. Interestingly, the (Z)-isomer (lower structure) eliminates more rapidly than the (E)-isomer (upper structure), again showing a preference for anti-orientation of eliminating groups. C6H5CH=CBrC6H5 + KOH > C6H5C≡CC6H5 + KBr + H2O
Preparation of Alkynes by DehydrohalogenationThe last reaction shown above suggests that alkynes might be prepared from alkenes by a two stage procedure, consisting first of chlorine or bromine addition to the double bond, and secondly a base induced double dehydrohalogenation. For example, reaction of 1-butene with bromine would give 1,2-dibromobutane, and on treatment with base this vicinal dibromide would be expected to yield 1-bromo-1-butene followed by a second elimination to 1-butyne. CH3CH2CH=CH2 + Br2 > CH3CH2CHBrCH2Br + base > CH3CH2CH=CHBr + base > CH3CH2C≡CH In practice this strategy works, but it requires care in the selection of the base and solvent. If KOH in alcohol is used, the first elimination is much faster than the second, so the bromoalkene may be isolated if desired. Under more extreme conditions the second elimination takes place, but isomerization of the triple bond also occurs, with the more stable isomer (2-butyne) being formed along with 1-butyne, even becoming the chief product. To facilitate the second elimination and avoid isomerization the very strong base sodium amide, NaNH2, may be used. Since ammonia is a much weaker acid than water (by a factor of 1018), its conjugate base is proportionally stronger than hydroxide anion (the conjugate base of water), and the elimination of HBr from the bromoalkene may be conducted at relatively low temperature. Also, the acidity of the sp-hybridized C-H bond of the terminal alkyne traps the initially formed 1-butyne in the form of its sodium salt. CH3CH2C≡CH + NaNH2 > CH3CH2C≡C:() Na(+) + NH3 An additional complication of this procedure is that the 1-bromo-1-butene product of the first elimination (see previous equations) is accompanied by its 2-bromo-1-butene isomer, CH3CH2CBr=CH2, and elimination of HBr from this bromoalkene not only gives 1-butyne (base attack at C-1) but also 1,2-butadiene, CH3CH=C=CH2, by base attack at C-3. Dienes of this kind, in which the central carbon is sp-hybridized, are called allenes and are said to have cumulated double bonds. They are usually less stable than their alkyne isomers.
Elimination Reactions1. The E2 ReactionWe have not yet considered the factors that influence elimination reactions, such as example 3 in the group presented at the beginning of this section. (3) (CH3)3C-Br + CN() > (CH3)2C=CH2 + Br() + HCN We know that t-butyl bromide is not expected to react by a SN2 mechanism. Furthermore, the ethanol solvent is not sufficiently polar to facilitate a SN1 reaction. The other reactant, cyanide anion, is a good nucleophile; and it is also a decent base, being about ten times weaker than bicarbonate. Consequently, a base-induced elimination seems to be the only plausible reaction remaining for this combination of reactants. To get a clearer picture of the interplay of these factors consider the reaction of a 2Ί-alkyl halide, isopropyl bromide, with two different nucleophiles.
In the methanol solvent used here, methanethiolate has greater
nucleophilicity than methoxide by a factor of 100. Methoxide, on the
other hand is roughly 106
times more basic than methanethiolate. As a result, we see a clearcut
difference in the reaction products, which reflects nucleophilicity
(bonding to an electrophilic carbon) versus basicity (bonding to
a proton). Kinetic studies of these reactions show that they are both
second order (first order in RBr and first order in Nu:()),
suggesting a bimolecular mechanism for each. The substitution reaction
is clearly SN2.
The corresponding designation for the elimination reaction is E2.
An energy diagram for the single-step bimolecular E2 mechanism is shown
on the right. We should be aware that the E2 transition state is less
well defined than is that of SN2 reactions. More bonds are being broken and formed, with the
possibility of a continuum of states in which the extent of CH and CX
bond-breaking and C=C bond-making varies. For example, if the Rgroups
on the beta-carbon enhance the acidity of that hydrogen, then
substantial breaking of CH may occur before the other bonds begin to be
affected. Similarly, groups that favor ionization of the halogen may
generate a transition state with substantial positive charge on the
alpha-carbon and only a small degree of CH breaking. For most simple
alkyl halides, however, it is proper to envision a balanced transition
state, in which there has been an equal and synchronous change in all
the bonds. Such a model helps to explain an important regioselectivity
displayed by these elimination reactions.
By using the strongly basic hydroxide nucleophile, we direct these reactions toward elimination. In both cases there are two different sets of beta-hydrogens available to the elimination reaction (these are colored red and orange and the alpha carbon is blue). If the rate of each possible elimination was the same, we might expect the amounts of the isomeric elimination products to reflect the number of hydrogens that could participate in that reaction. For example, since there are three 1Ί-hydrogens (red) and two 2Ί-hydrogens (orange) on beta-carbons in 2-bromobutane, statistics would suggest a 3:2 ratio of 1-butene and 2-butene in the products. This is not observed, and the latter predominates by 4:1. This departure from statistical expectation is even more pronounced in the second example, where there are six 1Ί-beta-hydrogens compared with one 3Ί-hydrogen. These results point to a strong regioselectivity favoring the more highly substituted product double bond, an empirical statement generally called the Zaitsev Rule.
The main factor contributing to Zaitsev Rule behavior is the
stability of the alkene. We noted earlier that carbon-carbon double
bonds are stabilized (thermodynamically) by alkyl substituents, and that
this stabilization could be evaluated by appropriate
heat of hydrogenation measurements. Since the E2 transition
state has significant carbon-carbon double bond character, alkene
stability differences will be reflected in the transition states of
elimination reactions, and therefore in the activation energy of the
rate-determining steps. From this consideration we anticipate that if
two or more alkenes may be generated by an E2 elimination, the more
stable alkene will be formed more rapidly and will therefore be the
predominant product. This is illustrated for 2-bromobutane by the energy
diagram on the right. The propensity of E2 eliminations to give the more
stable alkene product also influences the distribution of product
stereoisomers. In the elimination of 2-bromobutane, for example, we find
that trans-2-butene is produced in a 6:1 ratio with its cis-isomer. Bredt's RuleThe importance of maintaining a planar configuration of the trigonal double-bond carbon components must never be overlooked. For optimum pi-bonding to occur, the p-orbitals on these carbons must be parallel, and the resulting doubly-bonded planar configuration is more stable than a twisted alternative by over 60 kcal/mole. This structural constraint is responsible for the existence of alkene stereoisomers when substitutuion patterns permit. It also prohibits certain elimination reactions of bicyclic alkyl halides, that might be favorable in simpler cases. For example, the bicyclooctyl 3Ί-chloride shown below appears to be similar to tert-butyl chloride, but it does not undergo elimination, even when treated with a strong base (e.g. KOH or KOC4H9). There are six equivalent beta-hydrogens that might be attacked by base (two of these are colored blue as a reference), so an E2 reaction seems plausible. The problem with this elimination is that the resulting double bond would be constrained in a severely twisted (non-planar) configuration by the bridged structure of the carbon skeleton. The carbon atoms of this twisted double-bond are colored red and blue respectively, and a Newman projection looking down the twisted bond is drawn on the right. Because a pi-bond cannot be formed, the hypothetical alkene does not exist. Structural prohibitions such as this are often encountered in small bridged ring systems, and are referred to as Bredt's Rule.
Bredt's Rule should not be applied blindly to all bridged ring systems. If large rings are present their conformational flexibility may permit good overlap of the p-orbitals of a double bond at a bridgehead. This is similar to recognizing that trans-cycloalkenes cannot be prepared if the ring is small (3 to 7-membered), but can be isolated for larger ring systems. The anti-tumor agent taxol has such a bridgehead double bond (colored red), as shown in the following illustration. The bicyclo[3.3.1]octane ring system is the smallest in which bridgehead double bonds have been observed. The drawing to the right of taxol shows this system. The bridgehead double bond (red) has a cis-orientation in the six-membered ring (colored blue), but a trans-orientation in the larger eight-membered ring.
2. Stereochemistry of the E2 Reaction
E2 elimination reactions of certain isomeric cycloalkyl halides show
unusual rates and regioselectivity that are not explained by the
principles thus far discussed. For example,
trans-2-methyl-1-chlorocyclohexane reacts with alcoholic KOH at a much
slower rate than does its cis-isomer. Furthermore, the product from
elimination of the trans-isomer is 3-methylcyclohexene (not predicted by
the Zaitsev rule), whereas the cis-isomer gives the predicted
1-methylcyclohexene as the chief product. These differences are
described by the first two equations in the following diagram.
The most sensible interpretation of the elimination reactions of 2- and
4-substituted halocyclohexanes is that this reaction prefers an anti
orientation of the halogen and the beta-hydrogen which is attacked
by the base. These anti orientations are colored in red in the above
equations. The compounds used here all have six-membered rings, so the
anti orientation of groups requires that they assume a diaxial
conformation. The observed differences in rate are the result of a
steric preference for
equatorial orientation of large substituents,
which reduces the effective concentration of conformers having an axial
halogen. In the case of the 1-bromo-4-tert-butylcyclohexane isomers, the
tert-butyl group is so large that it will always assume an equatorial
orientation, leaving the bromine to be axial in the cis-isomer and
equatorial in the trans. Because of symmetry, the two axial
beta-hydrogens in the cis-isomer react equally with base, resulting in
rapid elimination to the same alkene (actually a racemic mixture). This
reflects the fixed anti orientation of these hydrogens to the chlorine
atom. To assume a conformation having an axial bromine the trans-isomer
must tolerate serious crowding distortions. Such conformers are
therefore present in extremely low concentration, and the rate of
elimination is very slow. Indeed, substitution by hydroxide anion
predominates. To see the effect of steric hindrance at a beta carbon on the E2 transition state
3. The E1 ReactionJust as there were two mechanisms for nucleophilic substitution, there are two elimination mechanisms. The E1 mechanism is nearly identical to the SN1 mechanism, differing only in the course of reaction taken by the carbocation intermediate. As shown by the following equations, a carbocation bearing beta-hydrogens may function either as a Lewis acid (electrophile), as it does in the SN1 reaction, or a Brψnsted acid, as in the E1 reaction.
Thus, hydrolysis of tert-butyl chloride in a mixed solvent of water and acetonitrile gives a mixture of 2-methyl-2-propanol (60%) and 2-methylpropene (40%) at a rate independent of the water concentration. The alcohol is the product of an SN1 reaction and the alkene is the product of the E1 reaction. The characteristics of these two reaction mechanisms are similar, as expected. They both show first order kinetics; neither is much influenced by a change in the nucleophile/base; and both are relatively non-stereospecific. (CH3)3CCl + H2O > [ (CH3)3C(+) ] + Cl() + H2O > (CH3)3COH + (CH3)2C=CH2 + HCl + H2O To summarize, when carbocation intermediates are formed one can expect them to react further by one or more of the following modes:
1.
The cation may bond to a nucleophile to give a substitution product. Since the SN1 and E1 reactions proceed via the same carbocation intermediate, the product ratios are difficult to control and both substitution and elimination usually take place. Having discussed the many factors that influence nucleophilic substitution and elimination reactions of alkyl halides, we must now consider the practical problem of predicting the most likely outcome when a given alkyl halide is reacted with a given nucleophile. As we noted earlier, several variables must be considered, the most important being the structure of the alkyl group and the nature of the nucleophilic reactant. The nature of the halogen substituent on the alkyl halide is usually not very significant if it is Cl, Br or I. In cases where both SN2 and E2 reactions compete, chlorides generally give more elimination than do iodides, since the greater electronegativity of chlorine increases the acidity of beta-hydrogens. Indeed, although alkyl fluorides are relatively unreactive, when reactions with basic nucleophiles are forced, elimination occurs (note the high electronegativity of fluorine).
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