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Substitution Reaction Mechanisms
1. The SN2 Mechanism As described in the previous section, a majority of the reactions thus far described appear to proceed by a common single-step mechanism. This mechanism is referred to as the SN2 mechanism, where S stands for Substitution, N stands for Nucleophilic and 2 stands for bimolecular. Other features of the SN2 mechanism are inversion at the alpha-carbon, increased reactivity with increasing nucleophilicity of the nucleophilic reagent and steric hindrance to rear-side bonding, especially in tertiary and neopentyl halides. Although reaction 3 exhibits second order kinetics, it is an elimination reaction and must therefore proceed by a very different mechanism, which will be described later.
2. The SN1 Mechanism Reaction 7, shown at the end of the previous section, is clearly different from the other cases we have examined. It not only shows first order kinetics, but the chiral 3º-alkyl bromide reactant undergoes substitution by the modest nucleophile water with extensive racemization. In all of these features this reaction fails to meet the characteristics of the SN2 mechanism. A similar example is found in the hydrolysis of tert-butyl chloride, shown below. Note that the initial substitution product in this reaction is actually a hydronium ion, which rapidly transfers a proton to the chloride anion. This second acid-base proton transfer is often omitted in writing the overall equation, as in the case of reaction 7 above. (CH3)3C-Cl + H2O ——> (CH3)3C-OH2(+) + Cl(–) ——> (CH3)3C-OH + HCl
Although the
hydrolysis of tert-butyl chloride, as shown above, might be interpreted as an SN2
reaction in which the high and constant concentration of solvent water does not
show up in the rate equation, there is good evidence this is not the case.
First, the equivalent hydrolysis of ethyl bromide is over a thousand times
slower, whereas authentic SN2
reactions clearly show a large rate increase for 1º-alkyl halides. Second, a
modest increase of hydroxide anion concentration has no effect on the rate of
hydrolysis of tert-butyl chloride, despite the much greater nucleophilicity of
hydroxide anion compared with water.
Consequently, we
expect that 3º-alkyl halides will be more reactive than their 2º and
1º-counterparts in reactions that follow a SN1
mechanism. This is opposite to the reactivity order observed for the SN2
mechanism. Allylic and benzylic halides are exceptionally reactive by either
mechanism.
3. Activation by Electrophilic Cations Heterolytic cleavage of the carbon-halogen bond of alkyl halides may be facilitated by the presence of certain metal cations. In the extreme, carbocations may be generated as shown in the following equation, where R is alkyl or hydrogen, and M = Al (n=3) or Fe (n=3) or Sn (n=4) or Zn (n=2). R3C-X + MXn (reactivity = Al > Fe > Sn > Zn) ——> R3C(+) + MXn-X(–) Although this technique is useful for generating carbocation intermediates in hydrocarbon solvents, the metal halide reactants are deactivated in protic solvents such as water and alcohol, rendering these reactants relatively useless for inducing SN1 reactions. There is, however, a related halophilic reactant that accomplishes this. This compound is silver nitrate, and in aqueous or alcoholic solution it promotes ionization of the alkyl halide and the formation of SN1 products. When silver nitrate is used with 1º or 2º-alkyl halides, rearrangement may occur before the product formation stage. For example: (CH3)3CCH2-Br + H2O + AgNO3 ——> (CH3)2C(OH)CH2CH3 + AgBr + HNO3
Elimination Reactions For many combinations of alkyl halides and nucleophiles, elimination reactions may compete with substitution, or even be the predominant reaction path. If we hope to understand why one or the other mode of reaction is preferred in a given case, we must study elimination reactions with the same care as we studied substitution. 1. The E2 Reaction We have not yet considered the factors that influence elimination reactions, such as example 3 in the group presented at the beginning of this section. (3) (CH3)3C-Br + CN(–) ——> (CH3)2C=CH2 + Br(–) + HCN We know that t-butyl bromide is not expected to react by a SN2 mechanism. Furthermore, the ethanol solvent is not sufficiently polar to facilitate a SN1 reaction. The other reactant, cyanide anion, is a good nucleophile; and it is also a decent base, being about ten times weaker than bicarbonate. Consequently, a base-induced elimination seems to be the only plausible reaction remaining for this combination of reactants. To get a clearer picture of the interplay of these factors consider the reaction of a 2º-alkyl halide, isopropyl bromide, with two different nucleophiles.
In the methanol
solvent used here, methanethiolate has greater nucleophilicity than methoxide by
a factor of 100. Methoxide, on the other hand is roughly 106
times more basic than methanethiolate.
By using the strongly basic hydroxide nucleophile, we direct these reactions toward elimination. In both cases there are two different sets of beta-hydrogens available to the elimination reaction (these are colored red and orange and the alpha carbon is blue). If the rate of each possible elimination was the same, we might expect the amounts of the isomeric elimination products to reflect the number of hydrogens that could participate in that reaction. For example, since there are three 1º-hydrogens (red) and two 2º-hydrogens (orange) on beta-carbons in 2-bromobutane, statistics would suggest a 3:2 ratio of 1-butene and 2-butene in the products. This is not observed, and the latter predominates by 4:1. This departure from statistical expectation is even more pronounced in the second example, where there are six 1º-beta-hydrogens compared with one 3º-hydrogen. These results point to a strong regioselectivity favoring the more highly substituted product double bond, an empirical statement generally called the Zaitsev Rule.
The main factor
contributing to Zaitsev Rule behavior is the stability of the alkene. We noted
earlier that carbon-carbon double bonds are stabilized (thermodynamically) by
alkyl substituents, and that this stabilization could be evaluated by
appropriate
heat of
hydrogenation
measurements. Since the E2 transition state has significant carbon-carbon double
bond character, alkene stability differences will be reflected in the transition
states of elimination reactions, and therefore in the activation energy of the
rate-determining steps. From this consideration we anticipate that if two or
more alkenes may be generated by an E2 elimination, the more stable alkene will
be formed more rapidly and will therefore be the predominant product. This is
illustrated for 2-bromobutane by the energy diagram on the right. The propensity
of E2 eliminations to give the more stable alkene product also influences the
distribution of product stereoisomers. In the elimination of 2-bromobutane, for
example, we find that trans-2-butene is produced in a 6:1 ratio with its cis-isomer. Bredt's Rule The importance of maintaining a planar configuration of the trigonal double-bond carbon components must never be overlooked. For optimum pi-bonding to occur, the p-orbitals on these carbons must be parallel, and the resulting doubly-bonded planar configuration is more stable than a twisted alternative by over 60 kcal/mole. This structural constraint is responsible for the existence of alkene stereoisomers when substitutuion patterns permit. It also prohibits certain elimination reactions of bicyclic alkyl halides, that might be favorable in simpler cases. For example, the bicyclooctyl 3º-chloride shown below appears to be similar to tert-butyl chloride, but it does not undergo elimination, even when treated with a strong base (e.g. KOH or KOC4H9). There are six equivalent beta-hydrogens that might be attacked by base (two of these are colored blue as a reference), so an E2 reaction seems plausible. The problem with this elimination is that the resulting double bond would be constrained in a severely twisted (non-planar) configuration by the bridged structure of the carbon skeleton. The carbon atoms of this twisted double-bond are colored red and blue respectively, and a Newman projection looking down the twisted bond is drawn on the right. Because a pi-bond cannot be formed, the hypothetical alkene does not exist. Structural prohibitions such as this are often encountered in small bridged ring systems, and are referred to as Bredt's Rule.
Bredt's Rule should not be applied blindly to all bridged ring systems. If large rings are present their conformational flexibility may permit good overlap of the p-orbitals of a double bond at a bridgehead. This is similar to recognizing that trans-cycloalkenes cannot be prepared if the ring is small (3 to 7-membered), but can be isolated for larger ring systems. The anti-tumor agent taxol has such a bridgehead double bond (colored red), as shown in the following illustration. The bicyclo[3.3.1]octane ring system is the smallest in which bridgehead double bonds have been observed. The drawing to the right of taxol shows this system. The bridgehead double bond (red) has a cis-orientation in the six-membered ring (colored blue), but a trans-orientation in the larger eight-membered ring.
2. Stereochemistry of the E2 Reaction
E2 elimination
reactions of certain isomeric cycloalkyl halides show unusual rates and
regioselectivity that are not explained by the principles thus far discussed.
For example, trans-2-methyl-1-chlorocyclohexane reacts with alcoholic KOH at a
much slower rate than does its cis-isomer. Furthermore, the product from
elimination of the trans-isomer is 3-methylcyclohexene (not predicted by the
Zaitsev rule), whereas the cis-isomer gives the predicted 1-methylcyclohexene as
the chief product. These differences are described by the first two equations in
the following diagram.
The most sensible
interpretation of the elimination reactions of 2- and 4-substituted
halocyclohexanes is that this reaction prefers an anti orientation of the
halogen and the beta-hydrogen which is attacked by the base. These anti
orientations are colored in red in the above equations. The compounds used here
all have six-membered rings, so the anti orientation of groups requires that
they assume a diaxial conformation. The observed differences in rate are the
result of a steric preference for
equatorial
orientation of large substituents,
which reduces the effective concentration of conformers having an axial halogen.
In the case of the 1-bromo-4-tert-butylcyclohexane isomers, the tert-butyl group
is so large that it will always assume an equatorial orientation, leaving the
bromine to be axial in the cis-isomer and equatorial in the trans. Because of
symmetry, the two axial beta-hydrogens in the cis-isomer react equally with
base, resulting in rapid elimination to the same alkene (actually a racemic
mixture). This reflects the fixed anti orientation of these hydrogens to the
chlorine atom. To assume a conformation having an axial bromine the trans-isomer
must tolerate serious crowding distortions. Such conformers are therefore
present in extremely low concentration, and the rate of elimination is very
slow. Indeed, substitution by hydroxide anion predominates.
Having arrived at a useful and plausible model of the E2 transition state, we can understand why a bulky base might shift the regioselectivity of the reaction away from the most highly substituted double bond isomer. Steric hindrance to base attack at a highly substituted beta-hydrogen site would result in preferred attack at a less substituted site. To see the effect of steric hindrance at a beta carbon on the E2 transition state
3. The E1 Reaction Just as there were two mechanisms for nucleophilic substitution, there are two elimination mechanisms. The E1 mechanism is nearly identical to the SN1 mechanism, differing only in the course of reaction taken by the carbocation intermediate. As shown by the following equations, a carbocation bearing beta-hydrogens may function either as a Lewis acid (electrophile), as it does in the SN1 reaction, or a Brønsted acid, as in the E1 reaction.
Thus, hydrolysis of tert-butyl chloride in a mixed solvent of water and acetonitrile gives a mixture of 2-methyl-2-propanol (60%) and 2-methylpropene (40%) at a rate independent of the water concentration. The alcohol is the product of an SN1 reaction and the alkene is the product of the E1 reaction. The characteristics of these two reaction mechanisms are similar, as expected. They both show first order kinetics; neither is much influenced by a change in the nucleophile/base; and both are relatively non-stereospecific. (CH3)3C–Cl + H2O ——> [ (CH3)3C(+) ] + Cl(–) + H2O ——> (CH3)3C–OH + (CH3)2C=CH2 + HCl + H2O To summarize, when carbocation intermediates are formed one can expect them to react further by one or more of the following modes:
1.
The cation may bond to
a nucleophile to give a substitution product. Since the SN1 and E1 reactions proceed via the same carbocation intermediate, the product ratios are difficult to control and both substitution and elimination usually take place. Having discussed the many factors that influence nucleophilic substitution and elimination reactions of alkyl halides, we must now consider the practical problem of predicting the most likely outcome when a given alkyl halide is reacted with a given nucleophile. As we noted earlier, several variables must be considered, the most important being the structure of the alkyl group and the nature of the nucleophilic reactant. The nature of the halogen substituent on the alkyl halide is usually not very significant if it is Cl, Br or I. In cases where both SN2 and E2 reactions compete, chlorides generally give more elimination than do iodides, since the greater electronegativity of chlorine increases the acidity of beta-hydrogens. Indeed, although alkyl fluorides are relatively unreactive, when reactions with basic nucleophiles are forced, elimination occurs (note the high electronegativity of fluorine).
Summary of Factors Influencing Alkyl Halide Reactions The following table summarizes the expected outcome of alkyl halide reactions with nucleophiles. It is assumed that the alkyl halides have one or more beta-hydrogens, making elimination possible; and that low dielectric solvents (e.g. acetone, ethanol, tetrahydrofuran & ethyl acetate) are used. When a high dielectric solvent would significantly influence the reaction this is noted in red. Note that halogens bonded to sp2 or sp hybridized carbon atoms do not normally undergo substitution or elimination reactions with nucleophilic reagents.
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